The product of two consecutive integers is 72. The equation x(x + 1) = 72 represents the situation, whererepresents the smaller integer. Which equation can be factored and solved for the smaller integer?0 x² + x - 72=0x² + x + 72 = 00x² + 2x - 72=00x² + 2x + 72=0

Answer:x^2 + x - 72 = 0Step-by-step explanation:The equation x(x + 1) = 72, when expanded by doing the indicated multiplication, comes out to x^2 + x - 72 = 0.That's alll you have to do here.But if you want to go all the way and find the actual value of x (the smaller integer), factor x^2 + x - 72 = 0 as follows:(x - 8)(x + 9) = 0.  Setting each factor = to 0 separately, we obtain the solution set {-9, 8}.If we choose -9 to be the smaller integer, then the next integer is -8.  Note that (-9)(-8) = 72.If we choose 8 to be the smaller integer, then the next integer is 9.  Note that (9)(8) = 72.Note:  None of the four possible answers you've shared is correct.  The correct quadratic equation does not begin with 0; it begins with 1:1x^2 + x - 72 = 0