Answer:Step-by-step explanation:Cl2 + 2KBr → 2KCl + Br2 Given: 300g of Cl2 300g of KBr(a) Mass of Cl2 = 300g Molecular mass of Cl2 = 2(35.45) = 70.906 g/mol No.of moles of Cl2 = mass/molarmass = 300/70.906 =4.23 moles Mass of KBr = 300gMolar mass of KBr= 39+79.9 = 118.9g/molNo.of moles of KBr = 300/118.9 =2.52molesNow,Consider the equation:Cl2 +2KBr→ 2KCl + Br2 1 mole of Cl2 = 2 moles of KCl 4.23 moles of Cl2 = 2x4.23= 8.46 moles2 moles of KBr = 2 moles of KCl2.52 moles of KBr = 2.52 molesNow convert moles to mass,Mass of KCl produced by Cl2 = 8.46×70.906=599.8gMass of KCl produced by potassium bromide = 2.52×74.5=187.74g